Class 12MathematicsApplication of Derivatives
Tangents and Normals
Slope of tangent to y=f(x) at point (xโ,yโ): m = f'(xโ). Equation of tangent: y-yโ = m(x-xโ). Normal is perpendicular to tangent: slope of normal = -1/m. Equation of normal: y-yโ = (-1/m)(x-xโ). If tangent is horizontal: m=0. If tangent is vertical: m=undefined (normal is horizontal).
10 examples
Concept check 1
For Class 12 Mathematics, explain or solve a tangents and normals question from the chapter "Application of Derivatives". Focus on concept check and show the working clearly.
Definition to application 2
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Formula warm-up 3
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Reasoning practice 4
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Board-style short answer 5
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Mistake correction 6
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Visual interpretation 7
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Applied word problem 8
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Revision challenge 9
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Exam recap 10
For Class 12 Mathematics, explain or solve a tangents and normals question from the chapter "Application of Derivatives". Focus on exam recap and show the working clearly.